Use the third and final seesaw use to determine if the 12th person is the heavier or lighter islander (i.e. 2) They are different. There is an island with 12 islanders. Otherwise the one who stayed is the oddly weighted one. (seesaw measurement number 3), 2.A.2 if left is heavy New comments cannot be posted and votes cannot be cast. sideline: S1 S2 S3 S4, 2.A.1 if balanced Eleven weigh exactly the same amount, but one of them is slightly lighter or heavier. Work fast with our official CLI. Weigh 1 against 2. The See-Saw. The tricky bit for me was figuring out that the left/right/balance needed to be cross-referenced, then discovering a pattern for each islander, where; Note: Ive since found out this is a variation on a puzzle involving 12 balls and a set of scales, but the same solution works here too. The essence of the riddle is: "There are 12 men on an island. If they are different, the heavier of the two is the one we are looking for (and heavier). You can only use it three times.. Planned Maintenance scheduled March 2nd, 2023 at 01:00 AM UTC (March 1st, We've added a "Necessary cookies only" option to the cookie consent popup, Ticket smash for [status-review] tag: Part Deux. (seesaw measurement number 3), 2.A.3 if right is heavy sideline: S1 S2 S3 S4. How can you find out which islander is the one that has a different weight? If any pair gets on and the see-saw does *not* balance, set that pair aside from the rest--one of those two men is the 12th man. seesaw: R1 L2 L3 L4 L1 S2 S3 S4 (balanced) 42 votes, 14 comments. ((, Please explain your claim that is was not asked properly. Can a VGA monitor be connected to parallel port? (Second Use), If the see saw balances, remove all but one from the seesaw and put one of the remaining two opposite them. If they are unequal then the odd man is the one within last 2 being measured that is heavier / lighter based on the known weight difference (heavier / lighter). seesaw: S1 S2 S3 R1 R2 R3 (heavy) Riddle: There are 12 people on an island and one is heavier than the others. You have a seesaw to determine who is the odd one out but you must figure this out in three measurements of the seesaw or less.. 12 Islanders Teeter Totter Riddle There is an island with 12 islanders. If the light side men are all of equal weight, the heavy side is then ordered to switch positions until the balance is no longer achieved, when the balance is lost, the last man to move is the heavier man. ie. In a seesaw at a playground, the fulcrum (the center point) is the bar that supports the seesaw. Did the residents of Aneyoshi survive the 2011 tsunami thanks to the warnings of a stone marker? The most simple solution is to arrange the people on the scale so that they have a unique correlation with the total information available. The only thing you can use is a see-saw, which can balance one man or group of men against another man or group of men. The most simple solution is to arrange the people on the scale so that they have a unique correlation with the total information available. The best answers are voted up and rise to the top, Not the answer you're looking for? seesaw: S1 S2 S3 R1 R2 R3 (balanced) There are no scales or other weighing device on the island. Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. Similar logic will help us design all further comparisons. 11 weigh exactly the same amount, but one of them is slightly lighter or heavier. If the see-saw balances, we are sure that the oddly wieghted one is in the other group of 4. Can someone suggest how we can modify the answer above ? If they are the same, 7 is different (and lighter). If they are equal then that must mean the 12th person is the different one. Show Answer PREV NEXT by Mikhael Panju v1. It only takes a minute to sign up. Take 3 men from the group and measure against 3 neutral men from 1-8. 11 of them weigh the same and one of them is either slightly Solution 2c. Split the men into two(2) groups 'abcdef' and '123456'. L: sit on the left, R: sit on the right, -: don't sit on the seesaw.. Looking for more great riddles? The one who is heavier is the different man (and heavier). (Third Use), If the two groups of 4 don't balance remember which side was lighter, have three get off one end and the remaining person swap places with one of the other four. They wouldve had to supersize the episode and put a flowchart on screen for a solid five straight minutes. Number the men from 1 to 12. A Puzzle is presented where there are twelve identical looking islanders and a seesaw. The biggest problem is that you do not know whether the odd man is heavier or lighter. Weigh 9,10,11 against 1,2,3. Put 1 on one end and 2 on the other (Third Use) if one is lighter they are the odd weight otherwise it is 3. Now we know that the different man is among {9,10,11,12}. If balanced, the remaining unknonw is the odd one and can be determined in step 3. Why do we kill some animals but not others? Site design / logo 2023 Stack Exchange Inc; user contributions licensed under CC BY-SA. note this works equally well if the group was lighter, just replace terms for appropriate identification. However only three measurements are allowed. 7 Answers Sorted by: 42 Split this into three groups of four, A1, A2, A3, A4; B1, B2. Eleven weigh exactly the same amount, but one of them is slightly lighter or heavier. That's not true. If the see-saw balances, we are sure that the oddly wieghted one is in the other group of 4. I can do this in one move, where no one gets off the see saw, and they only get on it once. The ice cube and the basketball have the same weight. The odd man is in the group is in 9-12. The riddle, as you'll recall, is this: There are twelve men on an island. Three measurements in all. Lift student learning and family engagement to new heights with multimodal learning tools, intuitive messaging, and research-based curriculum. IF the 2 scales are unequal, then you know the odd man is in the set of 1-8. (Third Use)notethis works equally well if the group was lighter, just replace terms for appropriate identification. Thankyou for reading and understanding. Thanks, AeJey for making it so clear! You must figure out which. There you have it, no islanders ever get off the see saw, and they just get on it once. A_ the equilibrium of the see-saw remains unchanged, therefore the man of a different weight is now amongst group 'def123' or The side that rises will "scootch" down the length of the see saw, away from the fulcrum until both sides balance. Would the reflected sun's radiation melt ice in LEO? (seesaw measurement number 3), (first make sure you have the heavy side on the left), seesaw: L1 L2 L3 L4 (heavy) R1 R2 R3 R4 Use the {{3 remaining with known weight solution}} from solution 1a. Here is one way of working out which of the people on the island weighs a different amount. {{#media.media_details}} {{#media.focal_point}}, First weigh 1, 2, 3, 4 vs 5, 6, 7, 8 on the seesaw. Now, weigh the remaining eight men on the seesaw, four on each side. If A > B, then weigh A1, B1, and B2 against B3, B4, and C1. The island has no escapes, but there is a seesaw. Suppose the previous two groups were 1234 and 5678, shuffle them to create a new group of 5 and 4678 then three of the third four say abcd get on with 5 to get as an example abc5 and 4678. Are there basic weighing puzzles requiring adaptive strategies? You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. Ackermann Function without Recursion or Stack. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. It is trickier than most, combining mathematical ability and logic for a serious brainteaser. Use your second seesaw turn to measure the four men, two on each side, then use your third and final seesaw turn to figure out which of the lightweights is THE light man. (First Use). And if they are, then weigh 9, 10, 11 vs 1, 2, and 3. rev2023.3.1.43268. The first measurement of 4 vs. 4 was equal. It is of indeterminate length I wish for my see saw to be long enough to place 12 on either side, but only six will be on either side of the fulcrum. Both situations are ideal as they reveal to us which group is the control group or standard for the weight of eleven of the men. put A&B on the seesaw then put A&C ( 2 uses) logic will give you the answer. Thanks for the explanation, I think the part where you highlight the Islanders and why theyre heavier or lighter really made me understand what you were going on about. Presented below is a simpler solution. (Third Use), If the see saw is not balanced, remove one from each end. You can figure out both in three steps. (Detailed . It is impossible to know both for sure in only three steps.). All our articles and reviews are written independently by the Netmums editorial team. @emdee - Here is the link that you posted in the question. The second measurement was equal, so you know that the odd man is within the group 6-8. There are 12 men on an island. Each weighing can give 3 possible answers: left side heavier, right side heavier, or both sides equal. It is easier than everyone makes it. IF the measurement is equal then the odd man is 12. A seesaw is binary. Now put 7 on one end and 8 on the other. In this last case, the first and second measurements were unequal, but produced the same result. If the position of seesaw does not change and as an example say 5678 and then 4678 are heavier, we know that either 6 or 7 or 8 is oddly weighted. This page contains affiliate links, which means we may earn a small amount of money if a reader clicks through and makes a purchase. Connect and share knowledge within a single location that is structured and easy to search. By clicking Accept all cookies, you agree Stack Exchange can store cookies on your device and disclose information in accordance with our Cookie Policy. I like Rosa's answer squeeze until fatty confesses. All of these men weigh exactly If they are the same, 8 is the one we are looking for (and lighter). (We could always relabel the men so that this is true). c) If they are the same, then one of 3,4 is different. Does the double-slit experiment in itself imply 'spooky action at a distance'. It will halve 8 unknowns on the first balance, four on the second and two on the third. Brooklyn 99 Riddle Seesaw - Askworksheet How do you figure out which one is heavier? So the solution must involve cross-referencing the left, right or balanced measurements of different groups of islanders. Another coin weighing puzzle. sideline: L1 L2 L3 S4 L4 R4 Can patents be featured/explained in a youtube video i.e. In either scenario, the steps are basically the same. The nice thing about this approach is that the logic is very simple (you just need to know the pattern) and you will always find out whether the person is lighter or heavier. "There are 12 men on an island. 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Tsunami thanks to the warnings of a stone marker see saw is not balanced, remove one each... Aneyoshi survive the 2011 tsunami thanks to the top, not the answer above and you may use. Or lighter the oddly wieghted one is in the other group of 4 not be posted and votes can be... Them is slightly lighter or heavier ) if they are different, and research-based curriculum solution 2c supersize the and. Research-Based curriculum be cast or balanced measurements of different groups of islanders otherwise the one who stayed the... In either scenario, the remaining eight men on an island and they just on... Brooklyn 99 riddle seesaw - Askworksheet how do you figure out which islander is the wieghted! Are written independently by the Netmums editorial team information available if a gt... Flowchart on screen for a serious brainteaser a flowchart on screen for serious... Was not asked properly claim that is was not asked properly halve unknowns. 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